المناقشه (8)
حل1:
log4 (64) = r
4^R = 64
(r log(4) = log(64
(r = log(64)/log(4
r = 3
-------
حل2:
81 = 4
a^4= 81
= 3^4
a=4
-------
حل3:
Log2 (128) = K
2^K = 128
(K log(2) = log(128
(K = log(128)/log(2
K = 7
----------------
السؤال الثاني
Log3 (125)+ Log3 (64) - 31Log3 (20)+ Log3 (243)
قوانين Log
Log m x Log m y = Log m x y
Log m x – Log m y = Log m x/y
Log m x = n Log m x
Log x x = 1
Log m 1 = صفر
Log3 (125)* (64) - Log3 (20)*(31)+ Log3 (243)
{(Log3{ (125)* (64) / (20)*(31)* (243
(Log3( 8000) / (620)* (243
التاسعه والعاشره بس احلها انزلها ان شاءالله